Physics · Kinetic Theory of Gases

JEE Main 2026 — 5 April, Morning Shift — Question 7

Statement I : Change in internal energy of a system containing n mole of ideal gas can be written as ΔU=nCv(Tf−Ti)=nRγ−1(Tf−Ti)\Delta U = nC_v(T_f - T_i) = \frac{nR}{\gamma-1}(T_f - T_i), where γ=Cp/Cv\gamma = C_p/C_v. Statement II : Relation between degree of freedom ff and γ\gamma is γ=1+2f\gamma = 1 + \frac{2}{f}.

  1. Option A:

    Both A and R are true and R is the correct explanation of A

  2. Option B:

    Both A and R are true but R is NOT the correct explanation of A

    Correct
  3. Option C:

    A is true but R is false

  4. Option D:

    A is false but R is true

Answer: B

Step-by-step solution

Both statements are correct, but Statement II does not explain Statement I.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Physics
Chapter
Kinetic Theory of Gases
Topic
Equipartition Law of Energy and Degrees of Freedom
Statement I : Change in internal energy of a system containing n mole… | JEE Main 2026 PYQ with Solution · DhiX AI