Chemistry · Electrochemistry

JEE Main 2025 — 23 January, Evening Shift — Question 27

Standard electrode potentials for a few half cells are mentioned below:

ECu2+/Cu0=0.34 V,EZn2+/Zn0=−0.76 V\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^{0}=0.34 \mathrm{~V}, \mathrm{E}_{\mathrm{Zn}^{2+} / \mathrm{Zn}}^{0}=-0.76 \mathrm{~V}

EAg+/Ag0=0.80 V,EMg2+/Mg0=−2.37 V\mathrm{E}_{\mathrm{Ag}^{+} / \mathrm{Ag}}^{0}=0.80 \mathrm{~V}, \mathrm{E}_{\mathrm{Mg}^{2+} / \mathrm{Mg}}^{0}=-2.37 \mathrm{~V}

Which one of the following cells gives the most negative value of ΔGo\Delta \mathrm{G}^{\mathrm{o}} ?

  1. Option A:

    Zn∣Zn2+(1M)∥Ag+(1M)∣Ag\mathrm{Zn}\left|\mathrm{Zn}^{2+}(1 \mathrm{M}) \| \mathrm{Ag}^{+}(1 \mathrm{M})\right| \mathrm{Ag}

    Correct
  2. Option B:

    Zn∣Zn2+(1M)∣∣Mg2+(1M)∣Mg\mathrm{Zn}\left|\mathrm{Zn}^{2+}(1 \mathrm{M})\right|\left|\mathrm{Mg}^{2+}(1 \mathrm{M})\right| \mathrm{Mg}

  3. Option C:

    Ag∣Ag+(1M)∣∣Mg2+(1M)∣Mg\mathrm{Ag}\left|\mathrm{Ag}^{+}(1 \mathrm{M})\right|\left|\mathrm{Mg}^{2+}(1 \mathrm{M})\right| \mathrm{Mg}

  4. Option D:

    Cu∣Cu2+(1M)∥Ag+(1M)∣Ag\mathrm{Cu}\left|\mathrm{Cu}^{2+}(1 \mathrm{M}) \| \mathrm{Ag}^{+}(1 \mathrm{M})\right| \mathrm{Ag}

Answer: A

Step-by-step solution

∵ΔG∘=−nFE∘\because \Delta \mathrm{G}^{\circ}=-\mathrm{nFE}^{\circ}

Option (1) E∘=0.8+0.76\mathrm{E}^{\circ}=0.8+0.76

=1.56 V=1.56 \mathrm{~V}

∴ΔG∘=−2×F×1.56\therefore \Delta \mathrm{G}^{\circ}=-2 \times \mathrm{F} \times 1.56

=−3.12 V=-3.12 \mathrm{~V}

Option (2) E∘=−2.37+0.76\mathrm{E}^{\circ}=-2.37+0.76

=−1.61 V=-1.61 \mathrm{~V}

∴ΔG∘=−2×F×(−1.61)\therefore \Delta \mathrm{G}^{\circ}=-2 \times \mathrm{F} \times(-1.61)

=+3.22 V=+3.22 \mathrm{~V}

Option (3) E∘=−2.37−0.8\mathrm{E}^{\circ}=-2.37-0.8

=−3.17 V=-3.17 \mathrm{~V}

∴ΔG∘=−2×F×(−3.17)\therefore \Delta \mathrm{G}^{\circ}=-2 \times \mathrm{F} \times(-3.17)

=+6.34=+6.34

Option (4) E∘=0.8−0.34\mathrm{E}^{\circ}=0.8-0.34

=0.46 V=0.46 \mathrm{~V}

ΔG∘=−2×F×0.46\Delta \mathrm{G}^{\circ}=-2 \times \mathrm{F} \times 0.46

=−0.92 V=-0.92 \mathrm{~V}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Electrochemistry
Topic
Basics of Galvanic Cell
Standard electrode potentials for a few half cells are mentioned… | JEE Main 2025 PYQ with Solution · DhiX AI