JEE Main 2026 — 22 January, Morning Shift — Question 36

Let $\left[\mathrm{R}=\frac{\ell}{3 \mathrm{KA}}\right]$ $\mathrm{T}_{\mathrm{A}}=100 \bullet \frac{11 \mathrm{R} / 2}{\longrightarrow} \mathrm{~T}_{\mathrm{F}}=40$ $\begin{gathered} \left[\mathrm{H}=\frac{100-40}{\frac{11 \mathrm{R}}{2}}\right] \ldots \end{gathered}$ $\begin{gathered} H=\frac{100-T_{B}}{R} \ldots \ldots \end{gathered}$ $\begin{gathered} H=\frac{T_{E}-40}{3 R} \ldots . \end{gathered}$ using (1) and (2) $\begin{aligned} & 120=1100-11 \mathrm{~T}_{\mathrm{A}} & \mathrm{~T}_{\mathrm{B}}=89^{\circ} \mathrm{C} \end{aligned}$ using (1) and (3) $\mathrm{T}_{\mathrm{E}}=73^{\circ} \mathrm{C}$