Mathematics · Binomial Theorem

JEE Main 2024 — 29 January, Shift 2 — Question 28

Remainder when $64^{32^{32}}$ is divided by 9 is equal to

Answer: 1

Numerical answer — enter this value.

Let $32^{32}=\mathrm{t}$

$64^{32^{32}}=64^{\mathrm{t}}=8^{2 \mathrm{t}}=(9-1)^{2 \mathrm{t}}$

$=9 \mathrm{k}+1$

Hence remainder $=1$

Answer key and solution verified before publishing.

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