Mathematics · Sets and Relations

JEE Main 2024 — 29 January, Shift 2 — Question 29

Let the set C={(x,y)∣x2−2y=2023,x,y∈N}C=\left\{(x, y) \mid x^{2}-2^{y}=2023, x, y \in \mathbb{N}\right\}. Then ∑(x,y)∈C(x+y)\sum_{(x, y) \in C}(x+y) is equal to _______\_\_\_\_\_\_\_ .

Answer: 46

Numerical answer — enter this value.

Step-by-step solution

x2−2y=2023\mathrm{x}^{2}-2^{\mathrm{y}}=2023

⇒x=45,y=1\Rightarrow x=45, \mathrm{y}=1

∑(x,y)∈C(x+y)=46\sum_{(x, y) \in C}(x+y)=46

Answer key and solution verified before publishing.

Practise Sets and Relations

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Main 2024
Subject
Mathematics
Chapter
Sets and Relations
Topic
Sets
Let the set C= \ (x, y) mid x 2 -2 y =2023, x, y in mathbb N \ . Then… | JEE Main 2024 PYQ with Solution · DhiX AI