JEE Main 2026 — 5 April, Morning Shift — Question 66

One mole of phenol is treated with dilute $\mathrm{HNO}_{3}$ at 298 K to give a mixture of products. The mixture is separated by steam distillation. The seam volatile compound ( X ) is separated. The increase in percentage of oxygen in (X) with respect to phenol is $\_\_\_\_$ $10^{-1} \%$ (Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14$, O:16).