Number of moles of H + ions required by 1 mole of MnO 4 - to oxidise oxalate ion to CO 2 is .

Chemistry · Redox Reactions

JEE Main 2024 — 31 January, Shift 2 — Question 75

Number of moles of $\mathrm{H}^{+}$ ions required by 1 mole of $\mathrm{MnO}_{4}^{-}$ to oxidise oxalate ion to $\mathrm{CO}_{2}$ is $\qquad$ .

Answer: 8

Numerical answer — enter this value.

Step-by-step solution

$2 \mathrm{MnO}_{4}^{-}+5 \mathrm{C}_{2} \mathrm{O}_{4}^{2-}+16 \mathrm{H}^{+} \longrightarrow 2 \mathrm{Mn}^{2+}+10 \mathrm{CO}_{2}+8 \mathrm{H}_{2} \mathrm{O}$

$\therefore$ Number of moles of $\mathrm{H}^{+}$ ions required by 1 mole of $\mathrm{MnO}_{4}^{-}$ to oxidise oxalate ion to $\mathrm{CO}_{2}$ is 8

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Exam: JEE Main 2024
Paper: 31 January, Shift 2
Subject: Chemistry
Chapter: Redox Reactions
Topic: Types of Redox Reactions & Balancing of Redox Reactions