Chemistry · Periodicity of Elements and Periodic Properties

JEE Main 2025 — 22 January, Morning Shift — Question 31

Match the List-I with List-II and choose the correct answer from the options given below :

List-IList-II
(A)Al3+<Mg2+<Na+<F−\text{A}{{\text{l}}^{3+}}<\text{M}{{\text{g}}^{2+}}<\text{N}{{\text{a}}^{+}}<{{\text{F}}^{-}}(I)Ionisation Enthalpy
(B)B<C<O<N\text{B}<\text{C}<\text{O}<\text{N}(II)Metallic character
(C)B<Al<Mg<K\text{B}<\text{Al}<\text{Mg}<\text{K}(III)Electronegativity
(D)Si<P<S<Cl\text{Si}<\text{P}<\text{S}<\text{Cl}(IV)Ionic radii
  1. Option A:

    A-IV, B-I, C-III, D-II

  2. Option B:

    A-II, B-III, C-IV, D-I

  3. Option C:

    A-IV, B-I, C-II, D-III

    Correct
  4. Option D:

    A-III, B-IV, C-II, D-I

Answer: C

Step-by-step solution

The trends corresponding to each sequence are:

Al3+<Mg2+<Na+<F−→ionic radii\mathrm{Al^{3+} < Mg^{2+} < Na^{+} < F^{-}} \rightarrow \text{ionic\ radii} B<C<O<N→ionisation enthalpy\mathrm{B < C < O < N} \rightarrow \text{ionisation\ enthalpy} B<Al<Mg<K→metallic character\mathrm{B < Al < Mg < K} \rightarrow \text{metallic\ character} Si<P<S<Cl→electronegativity\mathrm{Si < P < S < Cl} \rightarrow \text{electronegativity}

Thus, the correct matching is A→IV,B→I,C→II,D→IIIA \rightarrow IV,\quad B \rightarrow I,\quad C \rightarrow II,\quad D \rightarrow III.

Thus, the correct answer is Option C.

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Periodicity of Elements and Periodic Properties
Topic
Periodicity in Chemical Properties (Ionization Energy, Electron Affinity, Electronegativity)
Match the List-I with List-II and choose the correct answer from the… | JEE Main 2025 PYQ with Solution · DhiX AI