Chemistry · Coordination Compounds

JEE Main 2025 — 8 April, Evening Shift — Question 2

Match List-I with List-II :

List-IList-II
A. [Ni(CO)4]\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]I. Tetrahedral, 2.8 BM
B. [Ni(CN)4]2−\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}II. Square planar, 0 BM
C. [NiCl4]2−\left[\mathrm{NiCl}_{4}\right]^{2-}III. Tetrahedral, 0 BM
D. [MnBr4]2−\left[\mathrm{MnBr}_{4}\right]^{2-}IV. Tetrahedral, 5.9 BM

Choose the correct answer from the options given below

  1. Option A:

    A(A( III) ,B(II),C(I),D(IV), B(I I), C(I), D(I V)

    Correct
  2. Option B:

    A(I),B(II),C(III),D(IV)A(I), B(I I), C(I I I), D(I V)

  3. Option C:

    A(IV),B(I),C(III),D(II)A(I V), B(I), C(I I I), D(I I)

  4. Option D:

    A(III),B(IV),C(II),D(I)\mathrm{A}(\mathrm{III}), \mathrm{B}(\mathrm{IV}), \mathrm{C}(\mathrm{II}), \mathrm{D}(\mathrm{I})

Answer: A

Step-by-step solution

A) Ni(CO)4→Ni(0)⇒sp3\mathrm{Ni}(\mathrm{CO})_{4} \rightarrow \mathrm{Ni}(0) \Rightarrow \mathrm{sp}^{3}, tetrahedral, 0 BM

(3d 10{ }^{10} )(pairing)

B) [Ni(CN)4]−−→Ni2+⇒dsp2\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{--} \rightarrow \mathrm{Ni}^{2+} \Rightarrow \mathrm{dsp}^{2}, square planar, 0 BM

(3d 8{ }^{8} )(pairing)

C) [NiCl4]2−→Ni2+\left[\mathrm{NiCl}_{4}\right]^{2-} \rightarrow \mathrm{Ni}^{2+} (no pairing) ⇒sp3\Rightarrow \mathrm{sp}^{3}, tetrahedral, 2.8 BM

D) [MnBr4]2−⇒Mn2+⇒3 d5\left[\mathrm{MnBr}_{4}\right]^{2^{-}} \Rightarrow \mathrm{Mn}^{2+} \Rightarrow 3 \mathrm{~d}^{5} (no pairing)

μ=5.9BM\mu=5.9 \mathrm{BM}

(A-III, B-II, C-I, D-IV)

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Coordination Compounds
Topic
Properties and importance of Coordination Complexes
Match List-I with List-II : List-I List-II --- --- A. [ Ni ( CO ) 4 ]… | JEE Main 2025 PYQ with Solution · DhiX AI