Physics · Electrostatics

JEE Main 2025 — 29 January, Morning Shift — Question 37

Match List-I with List-II.

List-IList-II
(A)Electric field inside (distance r > 0 from center) of a uniformly charged spherical shell with surface charge density s, and radius R.(I)σ/ε0\sigma /{{\varepsilon }_{0}}
(B)Electric field at distance r>0\text{r}>0 from a uniformly charged infinite plane sheet with surface charge density σ\sigma .(II)σ/2ε0\sigma /2{{\varepsilon }_{0}}
(C)Electric field outside (distance r > 0 from center) of a uniformly charged spherical shell with surface charge density s, and radius R(III)0
(D)Electric field between 2 oppositely charged infinite plane parallel sheets with uniform surface charge density σ\sigma .(IV)σε0r2\frac{\sigma }{{{\varepsilon }_{0}}{{\text{r}}^{2}}}

Choose the correct answer from the options given below :

  1. Option A:

    (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

  2. Option B:

    (A)-(IV), (B)-(II), (C)-(III), (D)-(I)

  3. Option C:

    (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

  4. Option D:

    (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

    Correct

Answer: D

Step-by-step solution

(A) →0\rightarrow 0 (III)

(B) →σ2ε0\rightarrow \frac{\sigma}{2 \varepsilon_{0}} (II)

(C) →σR2ε0r2\rightarrow \frac{\sigma \mathrm{R}^{2}}{\varepsilon_{0} \mathrm{r}^{2}} (No row matching)

(D) →σε0\rightarrow \frac{\sigma}{\varepsilon_{0}} (I)

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Electrostatics
Topic
Electric flux and Gauss's Law
Match List-I with List-II. List-I List-II --- --- --- --- (A)… | JEE Main 2025 PYQ with Solution · DhiX AI