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Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2025 — 3 April, Evening Shift — Question 6

Mass of magnesium required to produce 220 mL of hydrogen gas at STP on reaction with excess of dil. HCl is Given: Molar mass of Mgis 24 g mol−1\mathrm{Mg}^{\text {is }} 24 \mathrm{~g} \mathrm{~mol}^{-1}.

  1. Option A:

    235.7 g

  2. Option B:

    0.24 mg

  3. Option C:

    2.444 g

  4. Option D:

    236 mg

    Correct

Answer: D

Step-by-step solution

Mg+2HCl⟶MgCl2+H2\mathrm{Mg}+2 \mathrm{HCl} \longrightarrow \mathrm{MgCl}_{2}+\mathrm{H}_{2} (220 mL)

Moles of H2=22022400\mathrm{H}_{2}=\frac{220}{22400} moles

Mass of Mg=22022400×24=0.236 g=236mg\mathrm{Mg}=\frac{220}{22400} \times 24=0.236 \mathrm{~g}=236 \mathrm{mg}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
3 April, Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Chemical Equations, Stoichiometry and Limiting Reagent

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