Mathematics · Statistics

JEE Main 2025 — 23 January, Morning Shift — Question 16

Marks obtained by all the students of class 12 are presented in a frequency distribution with classes of equal width. Let the median of this grouped data be 14 with median class interval 12-18 and median class frequency 12 . If the number of students whose marks are less than 12 is 18 , then the total number of students is

Option A:
48
Option B:
44
Correct
Option C:
40
Option D:
52

Answer: B

Step-by-step solution

medain $=\ell+\left(\frac{\frac{\mathrm{N}}{2}-\mathrm{F}}{\mathrm{f}}\right) \times \mathrm{h}$

$=12+\left(\frac{\frac{N}{2}-18}{12}\right) \times 6=14$

$\Rightarrow\left(\frac{\frac{\mathrm{N}}{2}-18}{12}\right) \times 6=2$

$\frac{\mathrm{N}}{2}-18=4 \Rightarrow \mathrm{~N}=44$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 23 January, Morning Shift
Subject: Mathematics
Chapter: Statistics
Topic: Measures of Central Tendency