Mathematics · Complex Numbers

JEE Main 2026 — 28 January, Morning Shift — Question 5

Let z be a complex number such that ∣z−6∣=5|\mathrm{z}-6|=5 and ∣z+2−6i∣=5|z+2-6 i|=5. Then the value of z3+3z2−15z+141z^{3}+3 z^{2}-15 z+141 is equal to

  1. Option A:

    4242

  2. Option B:

    3737

  3. Option C:

    5050

    Correct
  4. Option D:

    6161

Answer: C

Step-by-step solution

Center of first circle C1(6,0),r1=5\mathrm{C}_{1}(6,0), \mathrm{r}_{1}=5

Center of second circle C2(−2,6),r2=5C_{2}(-2,6), r_{2}=5

∵C1C2=r1+r2\because \mathrm{C}_{1} \mathrm{C}_{2}=\mathrm{r}_{1}+\mathrm{r}_{2}

∴ common point Z is mid point of C1\mathrm{C}_{1} & C2\mathrm{C}_{2}

∴z=2+3i\therefore \mathrm{z}=2+3 \mathrm{i}

∴z2=4z−13\therefore \mathrm{z}^{2}=4 \mathrm{z}-13

∴z3=3z−52\therefore z^{3}=3 z-52

∴z3+3z2−15z+141=50\therefore z^{3}+3 z^{2}-15 z+141=50

Solution figure

Answer key and solution verified before publishing.

Practise Complex Numbers

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Main 2026
Subject
Mathematics
Chapter
Complex Numbers
Topic
Geometry of Complex Numbers
Let z be a complex number such that z -6 =5 and z+2-6 i =5 . Then the… | JEE Main 2026 PYQ with Solution · DhiX AI