Let the mid points of the sides of a triangle ABC be (5/2,7 ), (5/2,3 ) and (4,5). If its incentive is (h, k), then 3 h + k is equal to:

Mathematics · Straight lines

JEE Main 2026 — 2 April, Morning Shift — Question 61

Let the mid points of the sides of a triangle ABC be $\left(\frac{5}{2},7\right),\left(\frac{5}{2},3\right)$ and (4,5). If its incentive is (h, k), then $3\mathrm{h} + \mathrm{k}$ is equal to:

Option A:
11
Option B:
12
Option C:
13
Correct
Option D:
14

Answer: C

Step-by-step solution

$\mathrm{I}=\left(\frac{24}{9}, 5\right)$ $\therefore 3 \mathrm{~h}+\mathrm{k}=8+5=13$

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Exam: JEE Main 2026
Paper: 2 April, Morning Shift
Subject: Mathematics
Chapter: Straight lines
Topic: Special Points in a Triangle

Two vertices of a triangle are (0,2) and (4,3) . If its orthocentre is at the origin, then its third vertex lies in which quadrant?

Answer: C

Step-by-step solution

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