Let the area of the region \ (x, y): 0 leq x leq 3,0 leq y leq .min \ x 2 +2,2 x+2 \ \ be A. Then 12 A is equal to

Mathematics · Area under the Curves

JEE Main 2024 — 29 January, Shift 2 — Question 25

Let the area of the region $\{(x, y): 0 \leq x \leq 3,0 \leq y \leq$ $\left.\min \left\{x^{2}+2,2 x+2\right\}\right\}$ be A. Then 12 A is equal to

Numerical answer — enter this value.

$A=\int_{0}^{2}\left(x^{2}+2\right) d x+\int_{2}^{3}(2 x+2) d x$ $\mathrm{A}=\frac{41}{3}$

$12 \mathrm{~A}=41 \times 4=164$

Answer key and solution verified before publishing.

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