Mathematics · Functions

JEE Main 2025 — 4 April, Morning Shift — Question 25

Let f,g:(1,∞)→Rf, g:(1, \infty) \rightarrow \mathbb{R} be defined as f(x)=2x+35x+2f(x)=\frac{2 x+3}{5 x+2} and g(x)=2−3x1−xg(x)=\frac{2-3 x}{1-x}. If the range of the function

f∘g:[2,4]→Rf \circ g:[2,4] \rightarrow \mathbb{R} is [α,β][\alpha, \beta], then 1β−α\frac{1}{\beta-\alpha} is equal to

  1. Option A:

    68

  2. Option B:

    29

  3. Option C:

    2

  4. Option D:

    56

    Correct

Answer: D

Step-by-step solution

g(2)=4,g(4)=103g(2)=4, g(4)=\frac{10}{3}

ff is decreasing in (103,4)\left(\frac{10}{3}, 4\right)

∴α=f(4)=12\therefore \quad \alpha=f(4)=\frac{1}{2}

β=f(103)=2956\beta=f\left(\frac{10}{3}\right)=\frac{29}{56}

1β−α=12956−12=56\frac{1}{\beta-\alpha}=\frac{1}{\frac{29}{56}-\frac{1}{2}}=56

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Functions
Topic
Domain & range of functions
Let f, g:(1, ∞) rightarrow mathbb R be defined as f(x)=2 x+3/5 x+2… | JEE Main 2025 PYQ with Solution · DhiX AI