Start free

Mathematics · Complex Numbers

JEE Main 2025 — 29 January, Morning Shift — Question 63

Let ∣z1−8−2i∣≤1\left|z_{1}-8-2 i\right| \leq 1 and ∣z2−2+6i∣≤2\left|z_{2}-2+6 i\right| \leq 2, z1,z2∈Cz_{1}, z_{2} \in C. Then the minimum value of ∣z1−z2∣\left|z_{1}-z_{2}\right| is

  1. Option A:

    3

  2. Option B:

    7

    Correct
  3. Option C:

    13

  4. Option D:

    10

Answer: B

Step-by-step solution

figure

∵AB=100=10\because \mathrm{AB}=\sqrt{100}=10

∴∣Z1−Z2∣min =10−2−1=7\therefore\left|\mathrm{Z}_{1}-\mathrm{Z}_{2}\right|_{\text {min }}=10-2-1=7

Answer key and solution verified before publishing.

Practise Complex Numbers

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2025
Paper
29 January, Morning Shift
Subject
Mathematics
Chapter
Complex Numbers
Topic
Geometry of Complex Numbers
Let z 1 -8-2 i leq 1 and z 2 -2+6 i leq 2 , z 1 , z 2 in C . Then the… | JEE Main 2025 PYQ with Solution · DhiX AI