Mathematics · Functions

JEE Main 2025 — 23 January, Morning Shift — Question 6

Let f(x)=log⁡exf(x)=\log _{e} x and g(x)=x4−2x3+3x2−2x+22x2−2x+1g(x)=\frac{x^{4}-2 x^{3}+3 x^{2}-2 x+2}{2 x^{2}-2 x+1} . Then the domain of fog is

  1. Option A:

    R\mathbb{R}

    Correct
  2. Option B:

    (0,∞)(0, \infty)

  3. Option C:

    [0,∞)[0, \infty)

  4. Option D:

    [1,∞)[1, \infty)

Answer: A

Step-by-step solution

f(x)=ln⁡x\mathrm{f}(\mathrm{x})=\ln \mathrm{x}

g(x)=x4−2x3+3x2−2x+22x2−2x+1g(x)=\frac{x^{4}-2 x^{3}+3 x^{2}-2 x+2}{2 x^{2}-2 x+1}

Dg∈RD_{g} \in R

Df∈(0,∞)\mathrm{D}_{\mathrm{f}} \in(0, \infty)

For Dfog⇒g(x)>0\mathrm{D}_{\mathrm{fog}} \Rightarrow \mathrm{g}(\mathrm{x})>0

x4−2x3+3x2−2x+22x2−2x+1>0\frac{x^{4}-2 x^{3}+3 x^{2}-2 x+2}{2 x^{2}-2 x+1}>0

⇒x4−2x3+3x2−2x+2>0\Rightarrow x^{4}-2 x^{3}+3 x^{2}-2 x+2>0

Clearly x<0\mathrm{x}<0 satisfies which are included in option (1) only.

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Functions
Topic
Domain & range of functions
Let f(x)=log e x and g(x)=frac x 4 -2 x 3 +3 x 2 -2 x+2 2 x 2 -2 x+1… | JEE Main 2025 PYQ with Solution · DhiX AI