Mathematics · Sets and Relations

JEE Main 2024 — 8 April, Shift 2 — Question 16

Let A={2,3,6,8,9,11}A=\{2,3,6,8,9,11\} and B={1,4,5,10,15}B=\{1,4,5,10,15\} Let R be a relation on A×B\mathrm{A} \times \mathrm{B} define by (a,b)R(c,d)(\mathrm{a}, \mathrm{b}) \mathrm{R}(\mathrm{c}, \mathrm{d}) if and only if 3ad−7bc3 \mathrm{ad}-7 \mathrm{bc} is an even integer. Then the relation R is

  1. Option A:

    reflexive but not symmetric.

  2. Option B:

    transitive but not symmetric.

  3. Option C:

    reflexive and symmetric but not transitive.

    Correct
  4. Option D:

    an equivalence relation.

Answer: C

Step-by-step solution

A={2,3,6,8,9,11}(a,b)R(c,d)\quad A=\{2,3,6,8,9,11\} \quad(a, b) R(c, d)

B={1,4,5,10,15}3ad−7bcB=\{1,4,5,10,15\} \quad 3 \mathrm{ad}-7 \mathrm{bc}

Reflexive : (a,b)R(a,b)(a, b) R(a, b)

⇒3ab−7ba=−4ab\Rightarrow 3 \mathrm{ab}-7 \mathrm{ba}=-4 \mathrm{ab}

always even so it is reflexive.

Symmetric : If 3ad−7bc=3 \mathrm{ad}-7 \mathrm{bc}= Even

Case-I : odd odd

Case-II: even even

(c,d)R(a,b)⇒3bc−3ab(\mathrm{c}, \mathrm{d}) \mathrm{R}(\mathrm{a}, \mathrm{b}) \Rightarrow 3 \mathrm{bc}-3 \mathrm{ab}

Case-I : odd odd

Case-II : even even

so symmetric relation Transitive :

Set (3,4)R(6,4)(3,4) R(6,4) Satisfy relation

Set (6,4)R(3,1)(6,4) R(3,1) Satisfy relation

but (3,4)R(3,1)(3,4) R(3,1) does not satisfy relation so not transitive.

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Sets and Relations
Topic
Types of Relations
Let A=\ 2,3,6,8,9,11\ and B=\ 1,4,5,10,15\ Let R be a relation on A ×… | JEE Main 2024 PYQ with Solution · DhiX AI