Mathematics · Sets and Relations

JEE Main 2025 — 23 January, Evening Shift — Question 2

Let A={(x,y)∈R×R:∣x+y∣≥3}A=\{(x, y) \in \mathbf{R} \times \mathbf{R}:|x+y| \geq 3\} and B={(x,y)∈R×R:∣x∣+∣y∣≤3}B=\{(x, y) \in \mathbf{R} \times \mathbf{R}:|x|+|y| \leq 3\}. If

C={(x,y)∈A∩B:x=0\mathbf{C}=\{(\mathrm{x}, \mathrm{y}) \in \mathbf{A} \cap \mathbf{B}: \mathrm{x}=0 or y=0}\mathrm{y}=0\}, then ∑(x,y)∈C∣x+y∣\sum_{(x, y) \in C}|x+y| is :

  1. Option A:

    15

  2. Option B:

    18

  3. Option C:

    24

  4. Option D:

    12

    Correct

Answer: D

Step-by-step solution

C={(3,0),(−3,0),(0,3),(0,−3)}\mathrm{C}=\{(3,0),(-3,0),(0,3),(0,-3)\}

Σ∣x+y∣=12\Sigma|\mathrm{x}+\mathrm{y}|=12

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Sets and Relations
Topic
Sets
Let A=\ (x, y) in R × R : x+y geq 3\ and B=\ (x, y) in R × R : x + y… | JEE Main 2025 PYQ with Solution · DhiX AI