X ' is the number of electrons in t 2 g orbitals of the most stable complex ion among [ Fe ( NH 3 ) 6 ] 3+ , [ FeCl 6 ] 3- , [ Fe ( C 2 O 4 ) 3 ] 3- and [ Fe ( H 2 O ) 6 ] 3+ . The nature of oxide of vanadium of the type V 2 Ox is:

Chemistry · Coordination Compounds

JEE Main 2025 — 4 April, Evening Shift — Question 5

$X$ ' is the number of electrons in $t_{2 g}$ orbitals of the most stable complex ion among $\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ ,

$\left[\mathrm{FeCl}_{6}\right]^{3-}, \quad\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ and $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ . The nature of oxide of vanadium of the type

$\mathrm{V}_{2} \mathrm{Ox}$ is:

Option A:
Amphoteric
Correct
Option B:
Acidic
Option C:
Neutral
Option D:
Basic

Answer: A

Step-by-step solution

Among the given complexes $\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ is most stable due to chelation.

$\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}: \mathrm{Fe}^{3+}: \mathrm{t}_{2 \mathrm{~g}}^{5} \mathrm{e}_{\mathrm{g}}^{0}$

$x=5$

$\mathrm{V}_{2} \mathrm{O}_{5}$ is amphoteric

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 4 April, Evening Shift
Subject: Chemistry
Chapter: Coordination Compounds
Topic: Properties and importance of Coordination Complexes

Answer: A

Step-by-step solution

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