Chemistry · Coordination Compounds

JEE Main 2025 — 4 April, Evening Shift — Question 14

A metal complex with a formula $\mathrm{MCl}_{4} \cdot 3 \mathrm{NH}_{3}$ is involved in $s p^{3} d^{2}$ hybridisation. It upon reaction with excess of $\mathrm{AgNO}_{3}$ solution gives ' x ' moles of AgCl . Consider ' $x$ ' is equal to the number of lone pairs of electron present in central atom of $\mathrm{BrF}_{5}$ . Then the number of geometrical isomers exhibited by the complex is $\_\_\_\_\_$ -.

Answer: 2

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{AgNO}_{3}+$ Complex $\rightarrow 1 \mathrm{~mol} \mathrm{AgCl}$

Complex ion should be $\left[\mathrm{M}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right] \mathrm{Cl}$

Total number of geometrical isomers $=2$

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Exam: JEE Main 2025
Paper: 4 April, Evening Shift
Subject: Chemistry
Chapter: Coordination Compounds
Topic: Isomerism in Coordination Compounds

Answer: 2

Step-by-step solution

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