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Physics · Sound Waves

JEE Main 2025 — 3 April, Evening Shift — Question 54

In the resonance experiment, two air columns (closed at one end) of 100 cm and 120 cm long, give 15 beats per second when each one is sounding in the respective fundamental modes. The velocity of sound in the air column is

  1. Option A:

    370 m/s370 \mathrm{~m} / \mathrm{s}

  2. Option B:

    340 m/s340 \mathrm{~m} / \mathrm{s}

  3. Option C:

    360 m/s360 \mathrm{~m} / \mathrm{s}

    Correct
  4. Option D:

    335 m/s335 \mathrm{~m} / \mathrm{s}

Answer: C

Step-by-step solution

f0=v4Lf_{0}=\frac{v}{4 L}

Δf=v4{11−11.2}\Delta f=\frac{v}{4}\left\{\frac{1}{1}-\frac{1}{1.2}\right\}

15×4×1.20.2=v\frac{15 \times 4 \times 1.2}{0.2}=v 360=v360=v

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
3 April, Evening Shift
Subject
Physics
Chapter
Sound Waves
Topic
Vibrations in rod and Air Columns - Organ pipes
In the resonance experiment, two air columns (closed at one end) of… | JEE Main 2025 PYQ with Solution · DhiX AI