In the given figure an ammeter A consists of a 240 Ω coil connected in parallel to a 10 Ω shunt. The reading of the ammeter is mA .

Physics · Current Electricity

JEE Main 2024 — 6 April, Shift 2 — Question 56

In the given figure an ammeter A consists of a $240 \Omega$ coil connected in parallel to a $10 \Omega$ shunt. The reading of the ammeter is $\qquad$ mA .

Answer: 160

Numerical answer — enter this value.

Step-by-step solution

Req

$=140.4+\frac{240 \times 10}{240+10}$

Req $=140.4+\frac{2400}{250}$

Req. $=150 \Omega$ $\therefore$

Current in ammeter $\begin{aligned} & =\frac{24}{150} & =160 \mathrm{~mA} \end{aligned}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 6 April, Shift 2
Subject: Physics
Chapter: Current Electricity
Topic: Electrical Measuring Instruments