Physics · Current Electricity

JEE Main 2024 — 31 January, Shift 2 — Question 48

in the following circuit, the battery has an emf of 2 V and an internal resistance of 23Ω\frac{2}{3} \Omega. The power consumption in the entire circuit is _______\_\_\_\_\_\_\_ W.

Question figure

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

Req =43Ω\mathrm{R}_{\text {eq }}=\frac{4}{3} \Omega

∴P=V2Req =44/3=3 W\therefore \mathrm{P}=\frac{\mathrm{V}^{2}}{\mathrm{R}_{\text {eq }}}=\frac{4}{4 / 3}=3 \mathrm{~W}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Physics
Chapter
Current Electricity
Topic
Circuit Analysis, Kirchhoff's Law and Nodal Analysis
in the following circuit, the battery has an emf of 2 V and an… | JEE Main 2024 PYQ with Solution · DhiX AI