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Physics · Units, Dimensions & Error Analysis

JEE Main 2024 — 5 April, Shift 1 — Question 36

In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of:

  1. Option A:

    103910^{39}

    Correct
  2. Option B:

    101910^{19}

  3. Option C:

    102910^{29}

  4. Option D:

    103610^{36}

Answer: A

Step-by-step solution

Fe=kQ1Q2r2=9×109×1.6×10−19×1.6×10−19r2\quad \mathrm{F}_{\mathrm{e}}=\frac{\mathrm{kQ}_{1} \mathrm{Q}_{2}}{\mathrm{r}^{2}}=\frac{9 \times 10^{9} \times 1.6 \times 10^{-19} \times 1.6 \times 10^{-19}}{\mathrm{r}^{2}}

Fg=Gm1 m2r2=6.67×10−11×9.1×10−31×1.6×10−27r2\mathrm{F}_{\mathrm{g}}=\frac{\mathrm{Gm}_{1} \mathrm{~m}_{2}}{\mathrm{r}^{2}}=\frac{6.67 \times 10^{-11} \times 9.1 \times 10^{-31} \times 1.6 \times 10^{-27}}{\mathrm{r}^{2}}

FeFg≅0.23×1040≅2.3×1039\frac{\mathrm{F}_{\mathrm{e}}}{\mathrm{F}_{\mathrm{g}}} \cong 0.23 \times 10^{40} \cong 2.3 \times 10^{39}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
5 April, Shift 1
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Significant Figures and Error Analysis

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