Physics · Moving Charges and Magnetic Field

JEE Main 2024 — 5 April, Shift 1 — Question 37

In a co-axial straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero

Option A:
inside the outer conductor
Option B:
in between the two conductors
Option C:
outside the cable
Correct
Option D:
inside the inner conductor

Answer: C

Step-by-step solution

$\oint \text{ }\!\!~\!\!\text{ }\!\!~\!\!\text{ {B}}\cdot \text{ }\!\!~\!\!\text{ d}\vec{\ell }={{\mu }_{0}}{{\text{i}}_{\text{enc}}}=0$

$\therefore \mathrm{B}=0$ outside the cable

Solution figure

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 5 April, Shift 1
Subject: Physics
Chapter: Moving Charges and Magnetic Field
Topic: Magnetic Field Due to Current-Carrying Wire - Biot-Savart Law

A 2 A current carrying straight metal wire of resistance 1 Omega , resistivity 2 × 10^-6 Omega m , area of cross-section 10 mm^2 and mass…

In a co-axial straight cable, the central conductor and the outer… | JEE Main 2024 PYQ with Solution · DhiX AI