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Chemistry · Periodicity of Elements and Periodic Properties

JEE Main 2024 — 1 February, Shift 1 — Question 61

In case of isoelectronic species the size of F−,Ne\mathrm{F}^{-}, \mathrm{Ne} and Na+\mathrm{Na}^{+}is affected by:

  1. Option A:

    Principal quantum number (n)

  2. Option B:

    None of the factors because their size is the same

  3. Option C:

    Electron-electron interaction in the outer orbitals

  4. Option D:

    Nuclear charge ( zz )

    Correct

Answer: D

Step-by-step solution

In F−,Ne,Na+\mathrm{F}^{-}, \mathrm{Ne}, \mathrm{Na}^{+}all have 1 s2,2 s2,2p61 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6} configuration. They have different size due to the difference in nuclear charge.

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
1 February, Shift 1
Subject
Chemistry
Chapter
Periodicity of Elements and Periodic Properties
Topic
Periodicity in Physical Properties (shielding and sizes)

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