Physics · Alternating Current

JEE Main 2025 — 23 January, Evening Shift — Question 71

In a series LCR circuit, a resistor of 300Ω300 \Omega, a capacitor of 25 nF and an inductor of 100 mH are used. For maximum current in the circuit, the angular frequency of the ac source is \qquad ×104\times 10^{4} radians s−1\mathrm{s}^{-1}.

Answer: 2

Numerical answer — enter this value.

Step-by-step solution

ω=1LC\omega=\frac{1}{\sqrt{\mathrm{LC}}}

ω=125×10−9×100×10−3\omega=\frac{1}{\sqrt{25 \times 10^{-9} \times 100 \times 10^{-3}}}

ω=10+65×10=2\omega=\frac{10^{+6}}{5 \times 10}=2

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Alternating Current
Topic
L-C Circuits oscillations and Quality Factor, Resonance
In a series LCR circuit, a resistor of 300 Ω , a capacitor of 25 nF… | JEE Main 2025 PYQ with Solution · DhiX AI