Physics · Geometrical Optics

JEE Main 2026 — 24 January, Morning Shift — Question 31

In a microscope of tube length 10 cm two convex lenses are arranged with focal length of 2 cm and 5 cm . Total magnification obtained with this system for normal adjustment is $(5)^{\mathrm{k}}$ . The value of k is $\_\_\_\_$

Option A:
2
Correct
Option B:
5
Option C:
3.5
Option D:
4

Answer: A

Step-by-step solution

$\mathrm{f}_{0}=2 \mathrm{~cm}, \mathrm{fe}=5 \mathrm{~cm}$ $\ell=10 \mathrm{~cm}, \mathrm{D}=25 \mathrm{~cm}$ $\mathrm{M}=\frac{\ell}{\mathrm{f}_{0}} \cdot \frac{\mathrm{D}}{\mathrm{f}_{\mathrm{e}}}=25$

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Exam: JEE Main 2026
Paper: 24 January, Morning Shift
Subject: Physics
Chapter: Geometrical Optics
Topic: Optical Instruments

The exit surface of a prism with refractive index n is coated with a material having refractive index frac n2 . When this prism is set for…

Answer: A

Step-by-step solution

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