Chemistry · Thermodynamics & Thermochemistry

JEE Main 2024 — 27 January, Shift 1 — Question 76

If three moles of an ideal gas at 300 K expand isotherrnally from 30dm330 \mathrm{dm}^{3} to 45dm345 \mathrm{dm}^{3} against a constant opposing pressure of 80 kPa , then the amount of heat transferred is \qquad J.

Answer: 1200

Numerical answer — enter this value.

Step-by-step solution

Using, first law of thermodynamics,

ΔU=Q+W\Delta \mathrm{U}=\mathrm{Q}+\mathrm{W}

ΔU=0\Delta \mathrm{U}=0 : Process is isothermal

Q=−W\mathrm{Q}=-\mathrm{W}

W=−PextΔV:\mathrm{W}=-\mathrm{P}_{\mathrm{ext}} \Delta \mathrm{V}: Irreversible

=−80×103(45−30)×10−3=-80 \times 10^{3}(45-30) \times 10^{-3}

=−1200 J=-1200 \mathrm{~J}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Thermodynamics & Thermochemistry
Topic
Internal Energy and the First Law
If three moles of an ideal gas at 300 K expand isotherrnally from 30… | JEE Main 2024 PYQ with Solution · DhiX AI