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Chemistry · Hydrocarbons

JEE Main 2024 — 27 January, Shift 1 — Question 77

3-Methylhex-2-ene on reaction with HBr in presence of peroxide forms an addition product (A). The number of possible stereoisomers for ' A ' is ____\_\_\_\_ .

Answer: 4

Numerical answer — enter this value.

Step-by-step solution

The structure of 3-methylhex-2-ene is:CH3−CH=C(CH3)−CH2−CH2−CH3\text{The structure of 3-methylhex-2-ene is:} \quad \text{CH}_3{-}\text{CH}{=}\text{C}(\text{CH}_3){-}\text{CH}_2{-}\text{CH}_2{-}\text{CH}_3 In the presence of peroxide, HBr adds via anti-Markovnikov rule: Br adds to C2, H adds to C3.\text{In the presence of peroxide, HBr adds via anti-Markovnikov rule: Br adds to C2, H adds to C3.} Both C2 and C3 become chiral centers.\text{Both C2 and C3 become chiral centers.} Number of stereoisomers=22=4\text{Number of stereoisomers} = 2^2 = \boxed{4}
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Exam
JEE Main 2024
Paper
27 January, Shift 1
Subject
Chemistry
Chapter
Hydrocarbons
Topic
Properties & Uses of Alkenes and Dienes
3-Methylhex-2-ene on reaction with HBr in presence of peroxide forms… | JEE Main 2024 PYQ with Solution · DhiX AI