Mathematics · Methods of Differentiation

JEE Main 2025 — 3 April, Morning Shift — Question 30

If y(x)=∣sin⁡xcos⁡xsin⁡x+cos⁡x+1272827111∣,x∈R\mathrm{y}(\mathrm{x})=\left|\begin{array}{ccc}\sin \mathrm{x} & \cos \mathrm{x} & \sin \mathrm{x}+\cos \mathrm{x}+1\\ 27 & 28 & 27\\ 1 & 1 & 1\end{array}\right|, \mathrm{x} \in \mathbb{R}, then d2ydx2+y\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}+\mathrm{y} is equal to:

  1. Option A:

    -1

    Correct
  2. Option B:

    28

  3. Option C:

    27

  4. Option D:

    1

Answer: A

Step-by-step solution

C3→C3−C1\mathrm{C}_{3} \rightarrow \mathrm{C}_{3}-\mathrm{C}_{1}

y(x)=∣sin⁡xcos⁡x1+cos⁡x27280110∣y(x)=\left|\begin{array}{ccc}\sin x & \cos x & 1+\cos x\\ 27 & 28 & 0\\ 1 & 1 & 0\end{array}\right|

y(x)=−(1+cos⁡x)y(x)=-(1+\cos x)

dydx=sin⁡x\frac{d y}{d x}=\sin x

d2ydx2=cos⁡x\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}=\cos \mathrm{x}

d2ydx2+y=−1\frac{d^{2} y}{d x^{2}}+y=-1

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Methods of Differentiation
Topic
Differentiation of Determinants
If y ( x )= begin array ccc sin x & cos x & sin x +cos x +1\\ 27 & 28… | JEE Main 2025 PYQ with Solution · DhiX AI