Physics · Units, Dimensions & Error Analysis

JEE Main 2026 — 22 January, Evening Shift — Question 26

If $\in, \mathrm{E}$ and t represent the free space permittivity, electric field and time respectively, then the unit of $\frac{\in E}{t}$ will be :

Option A:
Am
Option B:
$\mathrm{Am}^{2}$
Option C:
$A / m^{2}$
Correct
Option D:
$\mathrm{A} / \mathrm{m}$

Answer: C

Step-by-step solution

$\frac{\varepsilon \mathrm{E}}{\mathrm{t}}=\frac{\varepsilon}{\mathrm{t}} \frac{1}{4 \pi \varepsilon} \frac{\mathrm{q}}{\mathrm{r}^{2}}$ $\Rightarrow \frac{\mathrm{AT}}{\mathrm{TL}^{2}}=\left(\mathrm{AL}^{-2}\right)$ $\mathrm{A} / \mathrm{m}^{2}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 22 January, Evening Shift
Subject: Physics
Chapter: Units, Dimensions & Error Analysis
Topic: Units and Dimensions Analysis