If an air bubble of diameter 2 mm rises steadily through a liquid of density 2000 kg/m 3 at a rate of 0.5 cm/s , then the coefficient of viscosity of liquid is . (Take g =10 m/s 2 )

Physics · Mechanical Properties of Matter

JEE Main 2026 — 2 April, Evening Shift — Question 8

If an air bubble of diameter $2\mathrm{mm}$ rises steadily through a liquid of density $2000\mathrm{kg/m}^3$ at a rate of $0.5\mathrm{cm/s}$ , then the coefficient of viscosity of liquid is ______. (Take $\mathrm{g}=10\mathrm{m/s}^2$ )

Option A:
0.88
Option B:
8.8
Correct
Option C:
88.8
Option D:
0.088

Answer: B

Step-by-step solution

$F_B = F_V$ → $\rho_L \frac43\pi R^3 g = 6\pi\eta R v$ → $\eta = \frac{2}{9}\frac{\rho_L R^2 g}{v} = \frac{2}{9}\times\frac{2000\times10^{-6}\times10}{5\times10^{-3}} = \frac{80}{9}=8.88$

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Exam: JEE Main 2026
Paper: 2 April, Evening Shift
Subject: Physics
Chapter: Mechanical Properties of Matter
Topic: Viscosity

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Answer: B

Step-by-step solution

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