A mixture of carbon dioxide and oxygen has volume 8310 cm 3 , temperature 300 K , pressure 100 kPa and mass 13.2 g . The number of moles of carbon dioxide and oxygen gases in the mixture respectively are . (Assume both gases ideal) [ R =8.31 J/mol.K ]

Chemistry · Solutions and Colligative Properties

JEE Main 2026 — 2 April, Evening Shift — Question 7

A mixture of carbon dioxide and oxygen has volume $8310 \mathrm{cm}^3$ , temperature $300\mathrm{K}$ , pressure $100\mathrm{kPa}$ and mass $13.2\mathrm{g}$ . The number of moles of carbon dioxide and oxygen gases in the mixture respectively are ______. (Assume both gases ideal) [ $\mathrm{R}=8.31\mathrm{J/mol.K}$ ]

Option A:
0.15 and 0.18
Option B:
0.25 and 0.08
Option C:
0.21 and 0.12
Correct
Option D:
0.13 and 0.20

Answer: C

Step-by-step solution

Total moles = PV/RT = 0.333 44n1+32n2=13.2 n1+n2=0.333 → n1=0.211, n2=0.122

Answer key and solution verified before publishing.

Practise Solutions and Colligative Properties

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2026
Paper: 2 April, Evening Shift
Subject: Chemistry
Chapter: Solutions and Colligative Properties
Topic: Basics of Solutions

Solution A is prepared by dissolving 1 g of a protein (molar mass =50000 g mol^-1 ) in 0.5 L of water at 300 K . Its osmotic pressure is x…

Answer: C

Step-by-step solution

Practise Solutions and Colligative Properties

More Solutions and Colligative Properties questions from this paper