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Physics · Gravitation

JEE Main 2025 — 23 January, Evening Shift — Question 57

If a satellite orbiting the Earth is 9 times closer to the Earth than the Moon, what is the time period of rotation of the satellite? Given rotational time period of Moon =27=27 days and gravitational attraction between the satellite and the moon is neglected.

  1. Option A:

    1 Day

    Correct
  2. Option B:

    81 days

  3. Option C:

    27 days

  4. Option D:

    3 days

Answer: A

Step-by-step solution

T2∝R3\quad T^{2} \propto R^{3}

(TmTs)2=(RR/9)3\left(\frac{\mathrm{T}_{\mathrm{m}}}{\mathrm{T}_{\mathrm{s}}}\right)^{2}=\left(\frac{\mathrm{R}}{\mathrm{R} / 9}\right)^{3}

TmTs=(3)3\frac{T_{m}}{T_{s}}=(3)^{3}

⇒Ts=(2727)=1\Rightarrow \mathrm{T}_{\mathrm{s}}=\left(\frac{27}{27}\right)=1 day

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
23 January, Evening Shift
Subject
Physics
Chapter
Gravitation
Topic
Planetary Motion & Binary Star System (Kepler's Law)

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