Mathematics · Binomial Theorem

JEE Main 2024 — 27 January, Shift 1 — Question 5

If A denotes the sum of all the coefficients in the expansion of (1−3x+10x2)n\left(1-3 x+10 x^{2}\right)^{n} and BB denotes the sum of all the coefficients in the expansion of (1+x2)n\left(1+x^{2}\right)^{n}, then :

  1. Option A:

    A=B3A=B^{3}

    Correct
  2. Option B:

    3A=B3 A=B

  3. Option C:

    B=A3B=A^{3}

  4. Option D:

    A=3 B\mathrm{A}=3 \mathrm{~B}

Answer: A

Step-by-step solution

Sum of coefficients in the expansion of (1−3x+10x2)n=A\left(1-3 \mathrm{x}+10 \mathrm{x}^{2}\right)^{\mathrm{n}}=\mathrm{A}

then A=(1−3+10)n=8n(\mathrm{A}=(1-3+10)^{\mathrm{n}}=8^{\mathrm{n}}( put x=1)\mathrm{x}=1)

and sum of coefficients in the expansion of (1+x2)n=B\left(1+x^{2}\right)^{n}=B

Then B=(1+1)n=2nB=(1+1)^{\mathrm{n}}=2^{\mathrm{n}}

A=B3A=B^{3}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Binomial Theorem
Topic
Multinomial Theorem
If A denotes the sum of all the coefficients in the expansion of (1-3… | JEE Main 2024 PYQ with Solution · DhiX AI