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Physics · Kinetic Theory of Gases

JEE Main 2026 — 6 April, Evening Shift — Question 8

If 2 mole of an ideal monoatomic gas at temperature T, is mixed with 6 mole of another ideal monoatomic gas at temperature 2T then the temperature of mixture is:

  1. Option A:

    52T\frac{5}{2}T

  2. Option B:

    54T\frac{5}{4}T

  3. Option C:

    72T\frac{7}{2}T

  4. Option D:

    74T\frac{7}{4}T

    Correct

Answer: D

Step-by-step solution

For monoatomic, Cv=32RC_v = \frac{3}{2}R. Tmix=n1CvT1+n2CvT2n1Cv+n2Cv=2T+6×2T2+6=2T+12T8=14T8=74TT_{mix} = \frac{n_1 C_v T_1 + n_2 C_v T_2}{n_1 C_v + n_2 C_v} = \frac{2T + 6\times2T}{2+6} = \frac{2T+12T}{8} = \frac{14T}{8} = \frac{7}{4}T.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
6 April, Evening Shift
Subject
Physics
Chapter
Kinetic Theory of Gases
Topic
Energy of Gas and Gas Laws and Miscellaneous Problems