Chemistry · Structure of Atom

JEE Main 2026 — 23 January, Evening Shift — Question 57

Identify the incorrect statements:

A. 1224Mg^{24}_{12}\mathrm{Mg} represents 24 protons and 12 neutrons.

B. Wavelength of radiation of frequency 4.5×1015 s−14.5 \times 10^{15}\,\mathrm{s^{-1}} is 6.7×10−8 m6.7 \times 10^{-8}\,\mathrm{m}.

C. For λ1=900 nm\lambda_1 = 900\,\mathrm{nm} with energy E1E_1 and λ2=300 nm\lambda_2 = 300\,\mathrm{nm} with energy E2E_2, E1:E2=3:1E_1 : E_2 = 3 : 1.

D. Number of photons of wavelength 2000 pm2000\,\mathrm{pm} required to supply 1 J1\,\mathrm{J} energy is 1.006×10161.006 \times 10^{16}.

  1. Option A:

    A and D only

  2. Option B:

    A and C only

    Correct
  3. Option C:

    A and B only

  4. Option D:

    B and C only

Answer: B

Step-by-step solution

A: 1224Mg^{24}_{12}\mathrm{Mg} has 12 protons and 12 neutrons. Statement A is incorrect.

B: λ=cν=3×1084.5×1015=6.7×10−8 m\lambda = \frac{c}{\nu} = \frac{3 \times 10^8}{4.5 \times 10^{15}} = 6.7 \times 10^{-8}\,\mathrm{m}

Statement B is correct.

C: E∝1λE \propto \frac{1}{\lambda}

E1E2=λ2λ1=300900=13\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1} = \frac{300}{900} = \frac{1}{3}

So E1:E2=1:3E_1 : E_2 = 1 : 3

Statement C is incorrect.

D: Energy of one photon, E=hcλ=6.6×10−34×3×1082×10−9=9.9×10−17 JE = \frac{hc}{\lambda} = \frac{6.6 \times 10^{-34} \times 3 \times 10^8} {2 \times 10^{-9}} = 9.9 \times 10^{-17}\,\mathrm{J}

Number of photons, n=19.9×10−17=1.01×1016n = \frac{1}{9.9 \times 10^{-17}} = 1.01 \times 10^{16}

Statement D is correct. Thus, incorrect statements are A and C.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Structure of Atom
Topic
Electromagnetic Waves and Spectra
Identify the incorrect statements: A. 24 12 Mg represents 24 protons… | JEE Main 2026 PYQ with Solution · DhiX AI