Chemistry · Aldehydes and Ketones

JEE Main 2024 — 5 April, Shift 1 — Question 65

Identify 'A' in the following reaction :

Option A:
Option B:
Correct
Option C:
Option D:

Answer: B

Step-by-step solution

2-Butanone first forms a hydrazone with hydrazine, which on heating with KOH/ethylene glycol undergoes Wolff–Kishner reduction, converting the carbonyl group into $-\mathrm{CH_2}-$ , giving n-butane.

$\mathrm{CH_3COCH_2CH_3 \xrightarrow[\text{Ethylene \;glycol/ KOH}]{N_2H_4} CH_3CH_2CH_2CH_3}$

Thus, A = n-butane (Option B).

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 5 April, Shift 1
Subject: Chemistry
Chapter: Aldehydes and Ketones
Topic: Chemical properties of Aldehydes & Ketones