Physics · Geometrical Optics

JEE Main 2024 — 9 April, Shift 1 — Question 34

Given below are two statements: Statement (I): When an object is placed at the centre of curvature of a concave lens, image is formed at the centre of curvature of the lens on the other side. Statement (II): Concave lens always forms a virtual and erect image. In the light of the above statements,choose the correct answer from the options given below:

Option A:
Both statement I and statement Il are correct.
Option B:
Statement I is correct and statement Il is incorrect.
Option C:
Statement I is incorrect and statement Il is correct.
Correct
Option D:
Both statements 1 and statements ll are incorrect.

Answer: C

Step-by-step solution

$\frac{1}{v}-\frac{1}{u}=\frac{1}{\mathrm{f}}$

$\frac{1}{v}-\frac{1}{-2 f}=\frac{1}{-f}$

$\Rightarrow \frac{1}{\mathrm{v}}=\frac{-1}{2 \mathrm{f}} \Rightarrow \mathrm{v}=-2 \mathrm{f}$

$\frac{1}{\mathrm{v}}=\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{f}} \Rightarrow$ Virtual image of Real object.

In statement II, it is not mentioned that object is real or virtual hence Statement II is false.

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 9 April, Shift 1
Subject: Physics
Chapter: Geometrical Optics
Topic: Lenses and Their Combinations, Silvering of Lens