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Chemistry · Practical Organic Chemistry

JEE Main 2026 — 6 April, Evening Shift — Question 56

Given below are two statements :

Statement I: A mixture of C12H22O11\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11} (sugar) and NaCl can be separated by dissolving sugar in alcohol, due to differential solubility

Statement II : Rose essence from rose petals is separated by steam distillation due to its high volatility and insolubility in H2O\mathrm{H}_{2} \mathrm{O}.

In the light of the above statements, choose the correct answer from the options given below :

  1. Option A:

    Both Statement I and Statement II are true

  2. Option B:

    Both Statement I and Statement II are false

  3. Option C:

    Statement I is true Statement II is false

  4. Option D:

    Statement I is false Statement II is true

    Correct

Answer: D

Step-by-step solution

Sugar is soluble in alcohol not NaCl So they are separated by solvent extraction (or differential extraction) Rose essence oil is steam volatile so it is separated by steam distillation.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
6 April, Evening Shift
Subject
Chemistry
Chapter
Practical Organic Chemistry
Topic
Distillation and chromatography
Given below are two statements : Statement I: A mixture of C 12 H 22… | JEE Main 2026 PYQ with Solution · DhiX AI