Chemistry · p-Block Elements (Group 15-18)

JEE Main 2024 — 31 January, Shift 2 — Question 60

Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.

Statement I: S8\mathrm{S}_{8} solid undergoes disproportionation reaction under alkaline conditions to form S2−\mathrm{S}^{2-} and S2O32−\mathrm{S}_{2} \mathrm{O}_{3}^{2-}.

Statement II: ClO4−\mathrm{ClO}_{4}^{-}can undergo disproportionation reaction under acidic condition.

In the light of the above statements, choose the most appropriate answer from the options given below :

  1. Option A:

    Both statement I and statement Il are correct.

  2. Option B:

    Statement I is correct and statement Il is incorrect.

    Correct
  3. Option C:

    Statement I is incorrect and statement Il is correct.

  4. Option D:

    Both statements I and statements ll are incorrect.

Answer: B

Step-by-step solution

Statement I is Correct: Elemental sulphur (S8\mathrm{S_8}) undergoes disproportionation in alkaline medium, where sulphur is simultaneously reduced to sulphide (S2−\mathrm{S^{2-}}) and oxidised to thiosulphate (S2O32−\mathrm{S_2O_3^{2-}}).

Chemical reaction:

S8+12 NaOH→2 Na2S+Na2S2O3+6 H2O\mathrm{S_8 + 12\,NaOH \rightarrow 2\,Na_2S + Na_2S_2O_3 + 6\,H_2O}

Statement II is Incorrect: In the perchlorate ion (ClO4−\mathrm{ClO_4^-}), chlorine is present in its highest oxidation state (+7)(+7) and therefore cannot undergo disproportionation under acidic conditions.

Thus, Statement I is correct and Statement II is incorrect (Option B).

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
p-Block Elements (Group 15-18)
Topic
Compounds of Sulphur - preparation and properties
Given below are two statements, one is labelled as Statement I and… | JEE Main 2024 PYQ with Solution · DhiX AI