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Chemistry · p-Block Elements (Group 15-18)

JEE Main 2024 — 31 January, Shift 2 — Question 64

Choose the correct statements from the following

A. All group 16 elements form oxides of general formula EO2\mathrm{EO}_{2} and EO3\mathrm{EO}_{3} where E=S,Se,Te\mathrm{E}=\mathrm{S}, \mathrm{Se}, \mathrm{Te} and Po. Both the types of oxides are acidic in nature.

B. TeO2\mathrm{TeO}_{2} is an oxidising agent while SO2\mathrm{SO}_{2} is reducing in nature.

C. The reducing property decreases from H2 S\mathrm{H}_{2} \mathrm{~S} to H2Te\mathrm{H}_{2} \mathrm{Te} down the group.

D. The ozone molecule contains five lone pairs of electrons.

Choose the correct answer from the options given below:

  1. Option A:

    A and D only

  2. Option B:

    B and C only

  3. Option C:

    C and D only

  4. Option D:

    A and B only

    Correct

Answer: D

Step-by-step solution

(A) All group 16 elements form oxides of the EO2\mathrm{EO}_{2} and EO3\mathrm{EO}_{3} type where E=S\mathrm{E}=\mathrm{S}, Se, Te or Po .

(B) SO2\mathrm{SO}_{2} is reducing while TeO2\mathrm{TeO}_{2} is an oxidising agent.

(C) The reducing property increases from H2 S\mathrm{H}_{2} \mathrm{~S} to H2\mathrm{H}_{2} Te down the group.

(D) have six lone pairs

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
31 January, Shift 2
Subject
Chemistry
Chapter
p-Block Elements (Group 15-18)
Topic
Comparisons between the different compounds formed by Group 16 elements

More p-Block Elements (Group 15-18) questions from this paper

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