Chemistry · Periodicity of Elements and Periodic Properties
JEE Main 2026 — 22 January, Morning Shift — Question 61
Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.
Statement I: The halogen that makes longest bond with hydrogen in HX, has the smallest covalent radius in its group.
Statement II: A group 15 element's hydride has the lowest boiling point among corresponding hydrides of other group 15 elements. The maximum covalency of that element E is 4 .
In the light of the above statements, choose the correct answer from the options given below:
- Option A:
Both Statement I and Statement II are true.
- Option B:
Statement I is false but Statement II is true.
- Option C:Correct
Both Statement I and Statement II are false.
- Option D:
Statement I is true but Statement II is false.
Answer: C
Step-by-step solution
Statement I: Bond length in increases down the group because covalent radius increases. Thus, we have (bond length). The halogen forming longest bond is iodine, which has the largest covalent radius, not the smallest. Hence, Statement I is false.
Statement II: Among group 15 hydrides \mathrm{NH_3, PH_3, AsH_3, SbH_3}$$\mathrm{NH_3} has highest boiling point due to hydrogen bonding. Thus lowest boiling point is for . The element has maximum covalency , not . Hence, Statement II is also false.
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2026
- Subject
- Chemistry
- Chapter
- Periodicity of Elements and Periodic Properties
- Topic
- Valency, Diagonal Relationship, Inert Pair Effect & Other Miscellaneous Properties