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Chemistry · Periodicity of Elements and Periodic Properties

JEE Main 2025 — 2 April, Morning Shift — Question 4

Given below are two statements : one is labelled as Statement I and the other is labelled as Statement II:

Statement I: The metallic radius of AI is less than that of Ga .

Statement II: The ionic radius of Al1++\mathrm{Al}^{1++} is less than that of Ga3+\mathrm{Ga}^{3+}

In the light of the above statements, choose the correct answer from the options given below :

  1. Option A:

    Statement-I is incorrect but Statement-II is correct

    Correct
  2. Option B:

    Both Statement-I and Statement-II are incorrect

  3. Option C:

    Both Statement-I and Statement-II are correct

  4. Option D:

    Statement-I is correct but Statement-II is incorrect

Answer: A

Step-by-step solution

Metallic radius of Al is, greater than that of Ga due to ineffective shielding of d-electrons.

But ionic radius of Al3+\mathrm{Al}^{3+} is less than that of Ga3+\mathrm{Ga}^{3+} due to the absence of valence electrons.

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
2 April, Morning Shift
Subject
Chemistry
Chapter
Periodicity of Elements and Periodic Properties
Topic
Periodicity in Physical Properties (shielding and sizes)
Given below are two statements : one is labelled as Statement I and… | JEE Main 2025 PYQ with Solution · DhiX AI