Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II. Statement I: PF 5 and BrF 5 both exhibit sp 3 d hybridisation. Statement II: Both SF 6 and [ Co ( NH 3 ) 6 ] 3+ exhibit sp 3 d 2 hybridisation. In the light of the above statements, choose the correct answer from the options given below:

Statement I is true but Statement II is false

Both Statement I and Statement II are true

Statement I is false but Statement II is true

Chemistry · Chemical Bonding

JEE Main 2024 — 6 April, Shift 2 — Question 68

Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.

Statement I: $\mathrm{PF}_{5}$ and $\mathrm{BrF}_{5}$ both exhibit $\mathrm{sp}^{3} \mathrm{~d}$ hybridisation.

Statement II: Both $\mathrm{SF}_{6}$ and $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ exhibit $\mathrm{sp}^{3} \mathrm{~d}^{2}$ hybridisation.

In the light of the above statements, choose the correct answer from the options given below:

Option A:
Statement I is true but Statement II is false
Option B:
Both Statement I and Statement II are true
Option C:
Both Statement I and Statement II are false
Correct
Option D:
Statement I is false but Statement II is true

Answer: C

Step-by-step solution

Statement I is false: PF $_5$ has five bond pairs and no lone pair around phosphorus, resulting in a trigonal bipyramidal geometry and $sp^3d$ hybridisation. BrF $_5$ has five bond pairs and one lone pair (six electron pairs in total), giving a square pyramidal geometry with $sp^3d^2$ hybridisation.

Statement II is false: SF $_6$ has six bond pairs and no lone pair, giving an octahedral geometry with $sp^3d^2$ hybridisation. The complex $[\mathrm{Co(NH_3)_6}]^{3+}$ is a low-spin inner-orbital complex and exhibits $d^2sp^3$ hybridisation, not $sp^3d^2$ .

Thus, the correct answer is Both Statement I and Statement II are false.

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 6 April, Shift 2
Subject: Chemistry
Chapter: Chemical Bonding
Topic: Hybridization and VSEPR

Total number of species from the following with central atom utilising s p^2 hybrid orbitals for bonding is… NH 3, SO 2, SiO 2, BeCl 2, C 2…

Answer: C

Step-by-step solution

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