Chemistry · Chemical Bonding

JEE Main 2024 — 1 February, Shift 2 — Question 62

Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.

Statement (I) : π\pi-bonding molecular orbital has lower electron density above and below the internuclear axis.

Statement (II) : The π∗\pi^\ast (antibonding) molecular orbital has a node between the nuclei.

In the light of the above statements, choose the most appropriate answer from the options given below:

  1. Option A:

    Both Statement I and Statement II are false

  2. Option B:

    Both Statement I and Statement II are true

  3. Option C:

    Statement I is false but Statement II is true

    Correct
  4. Option D:

    Statement I is true but Statement II is false

Answer: C

Step-by-step solution

Statement I is Incorrect: In a π\pi-bonding molecular orbital, the electron density is maximum above and below the internuclear axis due to lateral overlap of atomic orbitals, not lower.

Statement II is Correct: A π∗\pi^\ast (antibonding) molecular orbital has a node between the nuclei because of out-of-phase overlap of atomic orbitals.

Thus, Statement I is false but Statement II is true (Option C).

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Chemical Bonding
Topic
Molecular Orbital Theory
Given below are two statements, one is labelled as Statement I and… | JEE Main 2024 PYQ with Solution · DhiX AI