Physics · Motion in one Dimension

JEE Main 2026 — 5 April, Morning Shift — Question 20

From $18$ m height above the ground a ball is dropped from rest. The height above the ground at which the magnitude of velocity equals the magnitude of acceleration (in the same set of units) due to gravity is ______ m. (Take $g = 10$ m/s² and neglect air resistance)

Answer: 13

Numerical answer — enter this value.

Step-by-step solution

Velocity v = gt, acceleration = g. They are equal when t = 1 s. Distance fallen = $\frac{1}{2}gt^2 = 5$ m. Height above ground = 18 - 5 = 13 m.

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Exam: JEE Main 2026
Paper: 5 April, Morning Shift
Subject: Physics
Chapter: Motion in one Dimension
Topic: Motion Under Gravity